Coding Round Mastery
Writing Clean Interview Code
4 min read
Clean code in interviews isn't about perfection -- it's about demonstrating that you write professional, readable code even under pressure.
Language Choice
| Language | Pros for Interviews | Cons |
|---|---|---|
| Python | Concise, readable, fast to write, built-in data structures | Slower runtime (rarely matters in interviews) |
| Java | Strong typing, explicit, popular in Big Tech | Verbose, more boilerplate |
| JavaScript | Universal, good for frontend roles | No built-in heap, unusual in some companies |
| C++ | Fast, shows systems knowledge | Most verbose, easy syntax errors |
Recommendation: Use Python unless the role specifically requires another language. It lets you write the most code in the least time.
Code Organization Rules
1. Meaningful Variable Names
# Bad
def f(a, t):
d = {}
for i, v in enumerate(a):
c = t - v
if c in d:
return [d[c], i]
d[v] = i
# Good
def two_sum(nums, target):
seen = {}
for index, num in enumerate(nums):
complement = target - num
if complement in seen:
return [seen[complement], index]
seen[num] = index
2. Helper Functions
Break complex logic into named functions:
# Without helpers (hard to follow)
def solve(board):
for i in range(9):
for j in range(9):
if board[i][j] == '.':
for c in '123456789':
if all(board[i][k] != c for k in range(9)) and \
all(board[k][j] != c for k in range(9)) and \
all(board[3*(i//3)+di][3*(j//3)+dj] != c
for di in range(3) for dj in range(3)):
board[i][j] = c
if solve(board): return True
board[i][j] = '.'
return False
return True
# With helpers (clear intent)
def solve(board):
def is_valid(row, col, num):
# Check row
if num in board[row]: return False
# Check column
if any(board[r][col] == num for r in range(9)): return False
# Check 3x3 box
box_r, box_c = 3 * (row // 3), 3 * (col // 3)
for r in range(box_r, box_r + 3):
for c in range(box_c, box_c + 3):
if board[r][c] == num: return False
return True
def backtrack():
for r in range(9):
for c in range(9):
if board[r][c] == '.':
for num in '123456789':
if is_valid(r, c, num):
board[r][c] = num
if backtrack(): return True
board[r][c] = '.'
return False
return True
return backtrack()
3. Early Returns
Reduce nesting with early returns:
# Deeply nested (hard to read)
def process(node):
if node:
if node.val > 0:
if node.left:
return process(node.left)
else:
return node.val
else:
return 0
else:
return -1
# Early returns (much cleaner)
def process(node):
if not node:
return -1
if node.val <= 0:
return 0
if not node.left:
return node.val
return process(node.left)
Common Pitfalls
| Pitfall | Fix |
|---|---|
| Off-by-one errors | Use range(n) for 0 to n-1; range(1, n+1) for 1 to n |
| Integer overflow | Python handles big integers; in Java/C++ use long |
| Null/None checks | Check before accessing .val, .next, .left |
| Modifying list while iterating | Iterate over a copy or use index-based loop |
| Forgetting to handle empty input | Add guard clause at the top |
Testing Your Code
After coding, trace through your solution:
# Your solution
def max_profit(prices):
min_price = float('inf')
max_profit = 0
for price in prices:
min_price = min(min_price, price)
max_profit = max(max_profit, price - min_price)
return max_profit
# Trace: prices = [7, 1, 5, 3, 6, 4]
# price=7: min=7, profit=0
# price=1: min=1, profit=0
# price=5: min=1, profit=4
# price=3: min=1, profit=4
# price=6: min=1, profit=5 ✓
# price=4: min=1, profit=5
# Result: 5 ✓
Interview Tip: After finishing your code, say: "Let me trace through this with our example to verify." This shows thoroughness and catches bugs before the interviewer does.
Next, let's cover the new AI-era skills that companies are testing in 2026. :::